17 double val = 0.0, frac, findx;
24 findx = (double)interval + 1.0;
28 for(i=0;i<interval;i++)
30 v1a[i] = frac * ((double)i + 1.0);
34 log_msg(
"V1A: %d: %.2f %.2f %.2f %.2f %.2f %.2f %.2f %.2f", interval,
37 log_msg(
"V2A: %d: %.2f %.2f %.2f %.2f %.2f %.2f %.2f %.2f", interval,
55 log_msg(
"P1 = %f; P2 = %f", v1, v2);
63 val = v1 *
v1a[j] + v2 *
v2a[j];
int makeInterpTable(int interval)
int log_msg(const char *fmt,...)